Question

the diagonals of a rectangle ABCD intersect at O. if angle boc =70;find angle ABO

Answer 1

Given in rectangle ABCD, ∠BOC = 70°

∠BOC = ∠AOD  [Vertically opposite angles are equal]

∠AOD = 70°

Since diagonal of a rectangle are equal and they bisect each other.

We can write OA = OB = OC = OD

Hence DAOD is an isosceles triangle.

⇒∠OAD = ∠ABO  [Angles opposite to equal sides of a triangle are equal]

Let ∠OAD = ∠ODA = x

∠OAD + ∠ABO +∠AOD = 180°

 ⇒ x + x + 70° = 180°

⇒ 2x = 110°

 ⇒ x = 55°

Hence angle ABO = 55°


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Answer 2

Answer:

Step-by-step explanation:

Here ur answer

Its 35

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