The diagonals of a rectangle ABCD intersect at O. If ∠BOC=68
,then find ∠ ODA.
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Answer:
The answer is 56
BOC = AOD
ADO = OAD
Then AOD + ADO + OAD = 180
Then, 68 + x + x = 180
2x = 180 - 68 = 112
x = 112/2 = 56
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