Question

The diagonals of a rectangle ABCD intersect at O. If ∠BOC = 68º, find ∠ODA.

Answer 1

Step-by-step explanation:

Since in a rec diagonal are equal and bisect each other

∴OD=OA

and ∠S opp to equal sides are equal

∴∠1=x

Now, In ΔODA

∠DOA=70

0

(vertically opp. ∠S)

x+∠1+70=180

0

(∠ sum prop)

and ∠1=x

∴x+x+70=180

2x=110

x=

2

110

x=55

0

⇒

∠ODA=55

0