Question

the diagonals of a rectangle ABCD intersect at O.If BOC=76°,find ODA

Answer 1

given ABCD is a rectangle and BOC =76°.
We know that BOC=AOD.So AOD= 76° also.
Now since we know that in a rectangle the diagonals bisect each other therefore OD=OA .Hence ODA=OAD. now in triangle OAD :
we know. AOD+ODA+OAD= 180°.
or. 76°+ODA +ODA= 180°
So. 2ODA=180-76
ODA=104/2
ODA=52°

Answer 2

boc=aod

(since opposite angles of a parallelogram is equal)

aod=76

Then,

aod+oda+oad=180

76+oda+oad=180

2oda=180-76

2oda=104

oda=104÷2

oda=52