Question

The diagonals of a rectangle ABCD intersect at O . lf angle BOC is 44 degree , find angle OAD.

Answer 1

hi friend

here your answer looking for

in a given figure,

angle BOC=angle A O D. (vertically opposite angle)

so,

angle AOD =44

in triangle AOD,

angle OAD= angle ODA. (opp angles of Iso. Tri.)

angle A O D + angle OAD + angle ODA= 180

44+angle OAD + angle OAD=180

2(angle OAD)=136

angle OAD=68

hope it's helpful to you

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Answer 2

$dear \: user \:$

⇒ ∠BOC=∠AOD [ Vertically opposite angles ]

∴ ∠AOD=44°

We know, that diagonals of rectangle are equal and they are bisect each other equally.

∴ OA=OB=OC=OD

In △AOD,

⇒ ∠OAD=∠ODA [ Base angles of equal sides ]

⇒ ∠AOD+∠OAD+∠ODA=180°

⇒ 44° +∠OAD+∠OAD=180

⇒ 2∠OAD=136

∴ ∠OAD=68°