Question

The diagonals of a rectangle ABCD intersects at O. If angle AOB=64°, find angle OCB​

Answer 1

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Answer 2

Answer:

angle C = angle B =90° [ corner angles of a rectangle is 90°]

1/2 angle C = 1/2 angel B

Angle OCB= angle OBC --(1)

In A OBC

angle OBC +angle OCB +angle BOC=180°

Angle OCB+angle OCB + 116° = 180°

[from eq 1]

2angle OCB = 180°-116

2 angle OCB = 64°

Angle OCB = 64/2

angle OCB = 32°

Step-by-step explanation:

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