Question

The diagonals of a rectangle ABCD meet at O.if angle BDC=44°.find angel OAD ​

Answer 1

Step-by-step explanation:

⇒ ∠BOC=∠AOD [ Vertically opposite angles ]

∴ ∠AOD=44

.

We know, that diagonals of rectangle are equal and they are bisect each other equally.

∴ OA=OB=OC=OD

In △AOD,

⇒ ∠OAD=∠ODA [ Base angles of equal sides ]

⇒ ∠AOD+∠OAD+∠ODA=180

⇒ 44 +∠OAD+∠OAD=180

⇒ 2∠OAD=136

∴ ∠OAD=68

Answer 2

Answer:

∠BOC=∠AOD [ Vertically opposite angles ]

∴ ∠AOD=44

o

.

We know, that diagonals of rectangle are equal and they are bisect each other equally.

∴ OA=OB=OC=OD

In △AOD,

⇒ ∠OAD=∠ODA [ Base angles of equal sides ]

⇒ ∠AOD+∠OAD+∠ODA=180

⇒ 44

+∠OAD+∠OAD=180

⇒ 2∠OAD=136

∴ ∠OAD=68