the diagonals of a rectangle are equal and perpendicular justify your answer
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because they rectangle propertis simple....
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If,AE = CE
BE = BE by reflexive property of congruence. A segment is congruent to itself.
AB = CB
So, by SSS congruency rule,
ΔAEB = ΔCEB
Now, we know that corresponding angles of congruent triangles are congruent. As ∠AEB and ∠CEB are corresponding angles.
∠AEB = ∠CEB.
But since they are supplementary angles
∠AEB + ∠CEB = 180°
So,
m∠AEB = m∠CEB = 90°
Therefore, the diagonals of the rectangle ABCD are perpendicular to each other.
And this what we wanted to proof.
Mark as the brainliest,if this answer helps.
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