the diagonals of a rectangle enclose an angle measure 78 and its perimeter is 36cm
Answers
Answer:
Step-by-step explanation:
The diagonals of a rectangle enclose an angle of measure 78 degree. If the perimeter of the rectangle is 36 cm, what is its area?
Let L & B denote the length & the breadth of the given rectangle respectively.
Hence from above data we get following relations,
L + B = 36/2 = 18
or L = 18 - B
L/B = tan (180° - 78°)/2
or (18 - B)/B = tan 51°
Answer:
The diagonals of a rectangle enclose an angle of measure 78 degree . If the perimeter of the rectangle is 36cm, what is its area?
Statement of the given problem,
The diagonals of a rectangle enclose an angle of measure 78 degree. If the perimeter of the rectangle is 36 cm, what is its area?
Let L & B denote the length & the breadth of the given rectangle respectively.
Hence from above data we get following relations,
L + B = 36/2 = 18
or L = 18 - B
L/B = tan (180° - 78°)/2
or (18 - B)/B = tan 51°
or B = 18/[1 + (tan 51°)] = 8.054 (cm) [Ans]