The diagonals of a rectangle PQRS intersect at O. If ∠ ROQ = 600, Find: (i) ∠ OSP (ii) ∠ RSO and (iii) ∠ PQO
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In the given figure, PQRS is a rectangle and its diagonals PR and QS intersect at O. If ∠POQ=110
o
, find the measure of ∠PSQ.
To find ∠PQO and ∠PSQ.
PQRS is a rectangle, and O is the intersection point of diagonals PR and SQ.
PR=SQ [Diagonals of rectangle are equal]
PO=Qo [Diagonals of rectangle bisect each other]
∴∠PQO=∠OPQ→(1) [Angles opposite to equal sides]
In △POQ ,
∠PQO+∠POQ+∠OPQ=180
∘
2∠PQO+110
∘
=180
∘
∠PQO=
2
180
∘
−110
∘
=35
∘
Now, in △PQS
∠PQS+∠QPS+∠PSQ=180
∘
35
∘
+90
∘
+∠PSQ=180
∘
∠PSQ=180
∘
−125
∘
=55
∘
I hope it helps you
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