the diagonals of a rhombus ABCD intersect at O,AO = 3cm , BO = 4cm then ,length of BC is
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Answer:
5 cm
Step-by-step explanation:
Apply Pythagoras in ∆ AOB
AB² = AO² + BO²
AB = √{3²+4²}
AB = √{9 + 16}
AB = √{25}
AB = 5 cm
AB = BC = CD = DA
5 cm = BC = CD = DA
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