Question

the diagonals of a rhombus ABCD intersect at O . if angle ADC =120 degree and OD = 6 cm . find OAD , side AB and perimeter of a rhombus ABCD?

Answer 1

AB = 12 cm & perimeter of rhombus = 48 cm

Step-by-step explanation:

Diagonals of rhombus bisects perpendicularly each other

OD = 6 cm

∠ADC = 120°

=> ∠ADO = 120°/2 = 60°

Cos 60°  = OD/AD

=> 1/2 = 6/AD

=> AD = 12

All sides of rhombus are equal

=> AB = 12 cm

Perimeter of rhombus = 4 * 12 = 48 cm

AB = 12 cm & perimeter of rhombus = 48 cm

Learn more:

In rhombus ABCD, AC = 40 cm and BD = 42 cm. Find the perimeter ...

https://brainly.in/question/14037947

ABCD is a rhombus of perimeter 16 CM. if it's one side AB and a ...

https://brainly.in/question/3899613