Question

The diagonals of a rhombus are 10 cm and 24 cm. Find
i) its area
ii) the length of a side
iii) its perimeter.
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Answer 1

Answer:

A=120cm²

Step-by-step explanation:

A=pq

2=10·24

2=120cm²

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Answer 2

Step-by-step explanation:

$i)a = \frac{pq}{2} \\ \\ = \frac{10.24}{2} = 120$

ii) Let ABCD be the rhombus where AC = 10 cm and BD = 24 cm.

• Let AC and BD intersect each other at O. Now, diagonals of rhombus bisect each other at right angles. Thus, we have.
• Since AOB is a right angled triangle, by pythagoras theorem, we have.
• Hence, AB = 13. Thus, length of each side of rhombus is 13 cm