Question

the diagonals of a rhombus are 10cm and 5.1cm . Find its area​

Answer 1

Given :

• Diagonal 1 = 5.1cm
• Diagonal 2 = 10 cm

$\begin{gathered} \\ \\ \end{gathered}$

To Find :

• Area = ?

Solution :

$\bigstar$Formula Used :

• ${\underline{\boxed{ \sf{\pmb{ Area{\small_{(Rhombus)}} = \dfrac{1}{2} \times D_1 \times D_2 }}}}}$

Where :

${\sf{ D_1 = Diagonal \; 1 }}$

${\sf{ D_2 = Diagonal \; 2 }}$

$\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}$

★ Calculating the Area :

$\begin{gathered} {\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{2} \times D_1 \times D_2 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{2} \times5.1 \times 10 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{2} \times \dfrac{51}{10} \times 10 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{\cancel2} \times \dfrac{51}{10} \times \cancel{10} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = 1 \times \dfrac{51}{10} \times 5 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \dfrac{51}{10} \times 5 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \dfrac{51}{\cancel{10}} \times \cancel5 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \dfrac{51}{2} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \cancel\dfrac{51}{2} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\orange{\pmb{\frak{ Area = 25.50 \; {cm}^{2} }}}}}}}} \end{gathered}$

$\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}$

★ Therefore :

❛❛ Area of the given Rhombus is 25.50 cm² . ❜❜

$\begin{gathered} \\ {\underline{\rule{300pt}{9pt}}} \end{gathered}$