Question

the diagonals of a rhombus are 12 centimetre and 16 cm find the length of each side of a rhombus


If it solved without Pythagoras theorem so please do it... If not as same solve it by explaining it

Answer 1

Step-by-step explanation:

let each side of rhombus be x cm

By Pythagoras Theorm

x^2=12^2+16^2

x^2=144+256

x^2=400

x=20cm

each side of rhombus is 20cm

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Answer 2

Answer:

AB=BC=CD=AD=10 cm

Step-by-step explanation:

the diagonals of a rhombus are 12 centimetre and 16 cm find the length of each side of a rhombus .

=> It cannot be solved without Pythagoras theorem.

Property: The diagonal of rhombus bisected each other at right angle,so four right triangles are formed .

In Right triangle OBC,apply Pythagoras Theorem

${(BC)}^{2} = {(OB)}^{2} + {(OC)}^{2} \\ \\ {(BC)}^{2} = {(8)}^{2} + ( {6)}^{2} \\ \\ {(BC)}^{2} = 64 + 36 \\ \\ {(BC)}^{2} = 100 \\ \\ BC = 10$

Sides of Rhombus are equal in length.

So,all the sides AB=BC=CD=AD=10 cm

Hope it helps you.