The diagonals of a rhombus are 12 cm and 16 cm. Find:
(1) The length of its one side, (ii) Its perimeter.
Answers
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1
Answer:
162
Step-by-step explanation:
you take 12 and times i by 16
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6
Given:
Diagonals of a rhombus = 12 cm, 16 cm
To find:
- Length of its 1 side
- It's perimeter
(Diagram is given in attachment)
Method:
1. We know that diagonals of a rhombus bisect each other and are perpendicular to each other.
Now,
In ∆AOB,
Applying Pythagoras theorem,
AB² = AO² + BO²
⇒AB² = 6² + 8²
⇒AB² = 36 + 64
⇒AB² = 100
⇒AB = √100
⇒AB = 10 cm
- Length of 1 side = 10 cm
2. We know that all sides are equal in rhombus.
∴ Perimeter = 4 × side
⇒Perimeter = 4 × 10
Perimeter = 40 cm
- Therefore Perimeter = 40 cm
Attachments:
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