Question

The diagonals of a rhombus are 12 cm and 16 cm. Find its perimeter.​

Answer 1

Answer:

40cm is the answer

Step-by-step explanation:

Diagonals of rhombus = 12cm and 16cm

half of diagonal = 6cm and 8cm

by using Pythagoras theorem

at the point o where diagonals are meet at the point there are angles formed 90°

so,

a (side) of rhombus =

$a \sqrt{6 { }^{2} } + 8 {}^{2}$

36+64 = 100 = 10cm

now, as we know the perimeter of rhombus

= 4a = 4×10 = 40cm