The diagonals of a rhombus are 12cm and 16cm. Find the area and also the length of the sides of the rhombus.
Answers
Answered by
2
this is your answer bro
Attachments:
Answered by
12
area of rhombus= (1/2)d1×d2 =(1/2)×12×16=96cm^2
the diagonals of a rhombus are perpendicular bisectors
therefore by using Pythagoras theorem we can find the length of its side
the two diagonals divide the rhombus into 4 triangles. consider one such ∆. here one angle is 90° and two sides are 6cm and 8cm( half of the diagonals)
let x be the side of rhombus
6^2+8^2=x^2
36+64=x^2
100=x^2
x=√100 =10 cm
the diagonals of a rhombus are perpendicular bisectors
therefore by using Pythagoras theorem we can find the length of its side
the two diagonals divide the rhombus into 4 triangles. consider one such ∆. here one angle is 90° and two sides are 6cm and 8cm( half of the diagonals)
let x be the side of rhombus
6^2+8^2=x^2
36+64=x^2
100=x^2
x=√100 =10 cm
Similar questions