Question

the diagonals of a rhombus are 12cm Nd 16 cm. find the area and also the length of the sides of the rhombus.​

Answer 1

Given:-

$diagonals \: of \: Rhombus$

To find:-

$area \: and \: length \: of \: sides$

Solution:-

⟹ Let ABCD the given Rhombus:-

⟹ With AC BD diagonals bisecting each other at right angles at O.

⟹ So AO= 1÷2×12

6 cm

⟹ BD= 1÷2×16

8 cm

⟹ In right angled triangle ADB

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⟹ By Pythagoreus theorem:-

(AB)²=(Ad)² + (OB)²

6² + 8²

36 + 64

(AB)²= 100

AB= 10 cm

⟹ Area of Rhombus:-

1÷2×d¹×d²

1÷2×12×16

96 cm²

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Answer 2

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☆Given:-

Diagonals of Rhombus

☆To find:-

area and length of sides

☆Solution:-

⟹ Let ABCD the given Rhombus:-

⟹ With AC BD diagonals bisecting each other at right angles at O.

⟹ So AO= 1÷2×12

⟹ AO = 6 cm

⟹ BD = 1÷2×16

⟹BD = 8 cm

⟹ In right angled triangle ADB

_____________________________________

⟹ By Pythagoreus theorem:-

(AB)²=(Ad)² + (OB)²

⟹(AB)² = 6² + 8²

⟹(AB)² = 36 + 64

⟹(AB)² = 100

⟹AB = 10 cm

⟹ Area of Rhombus:-

⟹1÷2×d¹×d²

⟹1÷2×12×16

⟹96 cm²

★・・・・・・★・・・♦・・・★・・・・・・★

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