The diagonals of a rhombus are 16 cm & 30 cm. Find the length of the side of the rhombus.
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Let ABCD a rhombus and o is the point where diagonals bisect each other
AC and BD are diagonals of rhombus
So,AC= 30cm and BD =16 cm
As we know the property of rhombus that diagonals bisect each other so they are equal
therefore AO=CO =15 cm and BO =OD=8cm
Now by applying Pythagoras theorem
AD^2=AO^2+OD^2
AD^2 =15^2 +8^2
AD^2=289
AD =17
Since all the sides of rhombus are congurent
hence side of rhombus is 17 cm
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Answer:
15 cm
Step-by-step explanation:
let side be x
Diagonal 1 = 16 cm
Diagonal 2 = 30 cm
Area =
1/2 X D¹ X D²
= 1/2 X 16 X 30
= 240 cm²
Area of rhombus is also = height X Side
therefore
16 X x = 240
x = 240/16 = 15 cm
therefore each side of rhombus is 15 cm
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