Question

the diagonals of a rhombus are 16 cm. and 30 cm respectively. Find its side.

Answer 1

If you mean "find it's perimeter"

Perimeter=4*(side)=4*17=68cm.

Answer 2

Answer-

Suppose ABCD are diagonals of the rhombus.

Since the diagonals of the rhombus bisect at right angle to each other,

Therefore, OD=DB/2=16/2=8

AND OC=AC/2=30/2=15

Now in right angled triangle DOC,

(DC)^2=(OD)^2+(OC)^2

(DC)^2=(8)^2+(15)^2

(DC)^2=64+225

(DC)^2=289

DC=√289=17 cm

Since rhombus has 4 sides Perimeter=

4*17 cm= 68 cm