Question

The diagonals of a rhombus are 16 m and 12 m, find:
in its area
(ii) length of a side (iii) perimeter​

Answer 1

Answer:

Length of side = 10m

Perimeter = 40m

Step-by-step explanation:

The diagonals bisect each other forming four equal right-angled triangles.

The side is the hypotenuse of the triangle, so we can use Pythagoras theory to solve this sum.

Length of diagonals/2 = 8 & 6 m

By Pythagoras theory,

${hypotenuse}^{2} \: = {8}^{2} + {6}^{2}$

= 64 + 36

= 100 =

${10}^{2}$

So, side = 10m

Perimeter = 4s

= 4(10) m

= 40 m

Hope it helps!!