Question

The diagonals of a rhombus are 16cm and 12 cm find the length of its side

Answer 1

Answer:

hi here is your answer

Step-by-step explanation:

(8) ^2 + (6)^2 =(h)^2

64+36

=100

side =10

I am sure that answer is correct

please mark it as a thanks

Answer 2

Answer:

Step-by-step explanation:let ABCD be a rhombos whose diagonals AB and BD intersect it O.

Then ,AC=16cm and BD =12cm

Since the diagonals of a rhombus bisect each other

We have, OA=OC=8cm;OB=OD=6cm

Again the diagonals of a rhombus bisect each other at right angles so,angle AOB= 90°.

let the length of each side of a rhombus be x cm then its right angle angle AOB by Pythagoras theorem we have:

AB^2=OA^2+OB^2

=>X^2=(8^2)+(9^2)

=>X^2=(64+81)

=>X=89