Question

The diagonals of a rhombus are 16cm and 12cm.

Find its i) area ii) length of its side iii) perimeter​

Answer 1

Given:

The first diagonal of a rhombus = 16 cm and

The second diagonal of a rhombus = 12 cm

We have to find,  its i) area ii) length of its side iii) perimeter​.

Solution:

i) The area of a rhombus = $\dfrac{1}{2}$ × First diagonal × Second diagonal

= $\dfrac{1}{2}$ × 16 cm × 12 cm

= 96 $cm^2$

Thus, the area of a rhombus is 96 $cm^2$.

ii) The length of the side a rhombus = $\sqrt{(\dfrac{d_1}{2} )^2+(\dfrac{d_2}{2} )^2}$

= $\sqrt{(\dfrac{16}{2} )^2+(\dfrac{12}{2} )^2}$

= $\sqrt{8^2+6^2}$ = $\sqrt{64+36}$

= $\sqrt{100}$ = 10 cm

Thus, the length of the side a rhombus is 10 cm.

iii) The perimeter of a rhombus = 4 × Side

= 4 × 10 cm

= 40 cm

Thus, the perimeter of a rhombus is 40 cm.

Answer 2

Answer:

the answer is 40 marks as brainlist