the diagonals of a rhombus are 16cm and 12cm find the perimeter
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Answered by
1
diagonal of rhombus = 16cm and 12cm
we know that,
diagonal of rhombus bisect each other at 90°
rhombus form four right triangles
height and base of right triangle= 8cm and 6cm
by using pythagoras theorem
side^2= 8^2+6^2
side^2= 64+36
side= 10cm
perimeter= 4×side
=4× 10
=40cm
please vote for answer.....
we know that,
diagonal of rhombus bisect each other at 90°
rhombus form four right triangles
height and base of right triangle= 8cm and 6cm
by using pythagoras theorem
side^2= 8^2+6^2
side^2= 64+36
side= 10cm
perimeter= 4×side
=4× 10
=40cm
please vote for answer.....
Answered by
7
Answer :
Perimeter = 40 cm
Step-by-step explanation :
Given :
Diagonal ( p ) = 16 cm
Diagonal ( q ) = 12 cm
We know that ;
Perimeter of rhombus = 2√p² + q²
= 2 √ 16² + 12²
= 2 √ 256 + 144
= 2 √ 400
= 2 × 20
= 40 cm
Hence, the perimeter of rhombus is 40 cm.
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