Question

the diagonals of a rhombus are 16m and 12m find perimeter ​

Answer 1

Answer:

Step-by-step explanation:

$d_{1} =16\\d_{2} = 12$

side of rhombus = $\sqrt{(\frac{16}{2})^{2} +(\frac{12}{2})^{2} } =\sqrt{8^{2} +6^{2} } =\sqrt{64+36} =\sqrt{100} =10$

perimeter = 4*s = 4 * 10 = 40m