Question

The diagonals of a rhombus are 18cm and 24cm. Find its area and perimeter

Answer 1

the answer is

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Answer 2

Answer:

Formula to find area of rhombus=>

=>(diagonal1×diaogonal2)/2

=>(18×24)/2

Area=216cm²

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Perimeter=4×side

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(Diagonals of a rhombus are perpendicular bisectors of each other, thus giving us four right triangles and splitting each diagonal in half,so we can find the side by applying Pythagoras therom)

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So it is now divided into 4 triangles.

Now to find its side,take any one triangle and apply Pythagoras therom.

Lets take the triangle BOC

Applying Pythagoras therom:-

H²=P²+B²

(OC)²=(BC)²+(OB)²

(9cm)²=(BC)²+(12cm)²

81cm=(BC)²+144cm

(BC)²=(144+81)cm

BC=√225cm

BC=15cm

So we got the side of rhombus=15cm

Perimeter of Rhombus=4×side

=4×15cm

=60cm ans....

Step-by-step explanation:

Hope that it would be helpful....