Question

the diagonals of a rhombus are 4 cm and 6 cm find the length of the side​

Answer 1

AC = 6 cm , then AO = 3cmt

BD = 4cm , then BO = 2 cm

[Diagonal bisects each other ]

By Pythagoras theorem

AB^2 = AO^2 + BO^2

AB^2 = 9 + 4 = 13

AB = $\sqrt{13}$ cm

Side of rhombus = $\sqrt{13}$ cm

Answer 2

In a Rhombus the diagonal bisect each other

so,

if ABCD is the Rhombus and their diagonal intersect at O then

AO = OC and BO = OD

now by applying Pythagoras theorem in triangle AOD,

AO = ½AC = 2cm

DO = ½BD = 3cm

AD² = AO²+ DO²

AD² = 2²+ 3²

AD = √4+9

AD = √13

AD= 3.605551275463989cm

hope it helps you

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