Question

the diagonals of a rhombus are 40 centimetre and 42 CM then find its area​

Answer 1

29 m

Solution :

The diagonals of a rhombus intersect at right angles and bisect each other.

In the figure,

OA=402cm=20cm,OB=422cm=21cm

AB=OA2+OB2−−−−−−−−−−√=202+212−−−−−−−−√cm=841−−−√cm=29m

Answer 2

GIVEN :-

• Diagonals of rhombus are 40cm , 42cm

TO FIND :-

• Area of rhombus

FORMULA TO KNOW:-

${Area\:of\:Rhombus} = \dfrac{1}{2} d_1 d_2$

Here they have given two diagonals we can find area of rhombus by using above formula Just If we substitute the values and simplify we get area of rhombus

Let,

${d_1 = 40cm}$

${d_2 = 42cm}$

${Area\:of\:Rhombus} = \dfrac{1}{2} d_1 d_2$

= $\frac{1}{2} \times 40cm \times 42cm$

= $20cm \times 42cm$

= $840cm {}^{2}$

So, area of rhombus = 840cm²

KNOW MORE :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²