The diagonals of a rhombus are 48 cm and 100 cm. Find the length of one side of the rhombus
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Perimeter of rhombus of side a=4a
⇒4a=100
⇒a=25cm.
Let AC=48cm
As diagonals bisect each other in rhombus
⇒AO=24cm
By Pythagoras theorem in ΔAOD, AD² = AO² +OD²
⇒OD² = √(625−576)
= 49
=7cm
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