Question

The diagonals of a Rhombus are 48cm and14 cm.Find its perimeter.​

Answer 1

Answer:

100cm^2

Step-by-step explanation:

Let ABCD be a rhombus whose

length of diagonals are 48 cm and 14 cm.

Then, OA=48/2=24cm and OB=14/2=7cm

We know that,

Diagonals of a rhombus perpendicularly bisect each other.

So, using pythagoras theorem,

OA^2+OB^2=AB2

or, 24^2+7^2=AB^2

or, 576+49=AB^2

or, 625=AB^2

or (25)^2=(AB)^2

i.e. AB=25cm

Now,

Perimeter of rhombus ABCD= 4*AB

=4*25

=100cm^2