Question

the diagonals of a rhombus are 4m and 3m respectively . find its (a) area (b) side​

Answer 1

Answer:

Formula of area of rhombus = 1/2 * diagonal 1 * diagonal 2 =/1/2 *4*3 = 6 m^2

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Answer 2

a.$6m^2$

b.$Side=2.5m$

Step-by-step explanation:

Let diagonals of rhombus

$d_1=4m,d_2=3m$

Area of rhombus=$\frac{1}{2}\times d_1\times d_2$

Where $d_1,d_2$ are diagonals of rhombus

Using the formula

a.Area of rhombus=$\frac{1}{2}\times 4\times 3=6m^2$

We know that diagonals of rhombus bisect perpendicularly

OA=$\frac{1}{2}AC=\frac{1}{2}\times 4=2m$

OB=$\frac{1}{2}BD=\frac{1}{2}\times 3=1.5 m$

In right triangle OAB

$AB^2=OA^2+OD^2$

Using Pythagoras theorem

$(hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2$

$AB^2=(2)^2+(1.5)^2=4+2.25=6.25$

$AB=\sqrt{6.25}=2.5$

Side of rhombus are equal

Therefore, side of rhombus=2.5m

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