Question

The diagonals of a rhombus are 72 cm and 30 cm respectively. What is its perimeter ? ​

Answer 1

Step-by-step explanation:

Hi ,

Given a rhombus you can directly find the perimeter using its :

1. Side : 4a

2. Diagonals(d1,d2): 2(sqrt(d1^2+d2^2))

here

d1=72

d2=30

 so

perimeter = 2 ( sqrt( 72^2 + 30^2 ) )

= 2*sqrt(6084)

=2*78

= 156 square cm

Hope it helped.

Please let me know if any further doubt.

Cheers !!!

Answer 2

Answer = 156.

Solution

Refer Formula for rhombus

$\bf \: perimeter \: = \sqrt{ {72}^{2} + {30}^{2} } = 156cm$