Question

The diagonals of a rhombus are 8 cm and 15 cm . Find its side .​

Answer 1

Answer:

8.5cm

Explanation:

Let ABCD be a rhombus

Diagonals :-  AC= 8cm

DB=15 cm

let AC and DB meet at a point O

AO = 8/2 = 4cm

OB = 15/2 = 7.5cm

By pythagoras theorem, AD² = AO² + OD²

AD² = 4² + 7.5²

AD² = 16 + 56.25

AD² = 72.25

AD = √72.56

AD = 8.5cm

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Answer 2

d1= 8 cm

d2= 15 cm

s=?

As, diagonals of rhombus are perpendicular bisectors of each other.

So, angle DOA= angle AOB= angle COB=angle DOC=90 degrees.

DO=BO=15/2 =>7.5 cm

AO=CO= 8/2 => 4 cm

Hence, in Triangle COB:

BC^2 = CO^2 + BO^2

BC^2 = 16 + 56.25

BC^2= 72.25

BC= root(72.25)

BC= 8.5 cm

Hence, side of rhombus =8.5 cm.