Question

the diagonals of a rhombus are 8 cm and 6 cm find the length of each side of rhombus

Answer 1

That your Answer Bro,
Diagonal 6cm = 3cm + 3cm = legs of right triangle within rhombus. 
Diagonal 8cm = 4cm + 4cm = legs of right triangle within rhombus. 
We need to find the side of the rhombus using the Pythagorean Theorem. 
After that, we use the formula P = 4s to find your perimeter. 
Let s = side of rhombus. 
3^2 + 4^2 = s^2 
9 + 16 = s^2 
25 = s^2 
5 = s 
Now that we know the side of the rhombus, apply P = 4s. 
P = 4(5) 
P = 20cm 

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Answer 2

let ABCD be a rhombus

AC and BD are diagonals.

AC=6, BD=8

diagonals of a rhombus bisect each other at right angles.

consider AC and BD meet at O

then in triangle AOD,

AD² = AO² + OD²

= (AC/2)² + (BD/2)²

= 3² + 4²

= 25

AD = √25

AD=5=side of rhombus

perimeter=4*side

=4*5=20.

therefore perimeter of rhombus is 20cm.