The diagonals of a rhombus are 8cm and 10cm. find the side of rhombus
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diagonals of rhombus bisect at 90⁰
Therefore ANGLE AOB = 90⁰
AND AO = OC
AO +OC = 10
AO +AO =10
2AO =10
AO = 5
SIMILARLY BO = OD = 4
NOW IN TRIANGLE AOB
(AB)² = 5² + 4²
= 25 +16
=41
AB = ROOT 41
THEREFORE , SIDE OF RHOMBUS = ROOT 41 ......
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