Question

the diagonals of a rhombus are 9 cm and 6 cm .it's area (in square cm​

Answer 1

Step-by-step explanation:

diagonal of the rhombus, d1= 9cm

d2=6cm

therefore,

area of the rhombus=1/2×d1×d2

=1/2×9×6

27 cm*2

Answer 2

Given:

The diagonals of a rhombus are 9cm and 6cm.

To find:

The area of the rhombus.

Solution:

The area of the rhombus whose diagonals are 9cm and 6cm respectively is 27cm².

We can solve the above mathematical problem with the following approach.

The area of a rhombus when the lengths of the diagonals of the rhombus are 'p' and 'q' respectively = $\frac{pq}{2}$.

According to the question, the length of the first diagonal is 9cm and the length of the second diagonal is 6cm.

On substituting the values in the above formula, we get:

Area of the rhombus = $\frac{9\times6}{2}= \frac{54}{2} = 27cm^2.$

Therefore, the area of the rhombus is 27cm².