The diagonals of a rhombus are in the ratio 3 4 and its area is 2400 side of the rhombus is
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the answer is f**k 2400
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HEY Buddy......!! here is ur answer
Given that : the diagonals of a rhombus in the ratio of 3:4 and it's area = 2400
Let, the diagonals of rhombus = 3x and 4x
As we know that : Area of rhombus = 1/2×(product of the diagonals)
Now, according to the question :
=> 1/2×(3x×4x) = 2400
=> x² = 400
=> x = 20
Then diagonals are : 3x = 3×20 = 60
and 4x = 4×20 = 80
From, the Pythagoras theoram we know that :
(side)² = (d1/2)²+(d2/2)²
=> (side)² = (60/2)²+(80/2)²
=> (side)² = (30)²+(40)² = 900+1600
=> (side)² = 2500 => side = 50
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
Given that : the diagonals of a rhombus in the ratio of 3:4 and it's area = 2400
Let, the diagonals of rhombus = 3x and 4x
As we know that : Area of rhombus = 1/2×(product of the diagonals)
Now, according to the question :
=> 1/2×(3x×4x) = 2400
=> x² = 400
=> x = 20
Then diagonals are : 3x = 3×20 = 60
and 4x = 4×20 = 80
From, the Pythagoras theoram we know that :
(side)² = (d1/2)²+(d2/2)²
=> (side)² = (60/2)²+(80/2)²
=> (side)² = (30)²+(40)² = 900+1600
=> (side)² = 2500 => side = 50
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
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