The diagonals of a rhombus are in the ratio 3 : 4.If its perimeter is 60 cm, find the lengths of
the sides and diagonals of the rhombus.
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Let the sides of rhombus be a
and diagonals be d
1
and d
2
perimeter =40cm
4a=40cm
a=10cm
Ratio of diagonals=3:4
d
2
d
1
=
4
3
d
1
=
4
3d
2
...(1)
Now,
a
2
=
4
d
1
2
+
4
d
2
2
d
1
2
+d
2
2
=4a
2
16
9d
2
2
+d
2
2
=4(10)
2
16
25d
2
2
=400
Square Rooting both sides
4
5d
2
=20
d
2
=16
put d
2
=16 in equation ...(1)
d
1
=12
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