Math, asked by jyotiirle, 7 months ago

The diagonals of a rhombus are in the ratio 3:4.The longer diagonal is 12 cm. Find the area of rhombus.

Answers

Answered by Anonymous
12

 \bf \huge {\underline {\underline \red{AnSwEr}}}

⠀⠀⠀⠀

Given

⠀⠀⠀⠀

  • Ratio of diagonals of rhombus = 3 : 4

⠀⠀⠀⠀

  • Longer diagonal = 12cm

⠀⠀⠀⠀

To Find

⠀⠀⠀⠀

  • Area of rhombus

⠀⠀⠀⠀

Solution

⠀⠀⠀⠀

Let the diagonals be 3x and 4x.

⠀⠀⠀⠀

d₁ = 3x

d₂ = 4x [ Longer diagonal ]

⠀⠀⠀⠀

According to question,

⠀⠀⠀⠀

Longer diagonal = 12

4x = 12

x = 12/4

x = 3cm.

⠀⠀⠀⠀

d₁ = 3x = 3 × 3 = 9cm

d₂ = 4x = 4 × 3 = 12cm

⠀⠀⠀⠀

Therefore, d₁ = 9cm and d₂ = 12cm

⠀⠀⠀⠀

\bf Area\:of\:Rhombus= \frac {1}{2}\times (d₁ × d₂)

⠀⠀⠀⠀

\bf\implies \frac {1}{2}\times (9 × 12 )

⠀⠀⠀⠀

\bf\implies 9\times 6

⠀⠀⠀⠀

\bf\implies 54cm^2

Answered by singhjaynandan679
0

Answer:

let diagonals of rhombus ABCD are AC=3Kand BD=4K.which meet at point o.

perimeter=4×side

40/4=side

10cm.=side=AB=BC=CD=DA.

in right angle triangle AOB

OA²+OB²=AB²

(AC/2)²+(BD)²=(10)²

(25K²)/4=100

K²=16

OK=+/-4

AC=3K=3×4=12cm.

BD=4K=4×4=16cm

each side=10cm.,

Similar questions