the diagonals of a rhombus are of length 6cm and 6cm. find the length of its sides
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dear friend,
4 * side
4 * 5 = 20
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4 * side
4 * 5 = 20
HOPE IT WILL HELP YOU
plzz mark me as brainliest
THANKS
ishananand1302:
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The diagonals bisector measure = 3 and 3 (half of 6)
Now , by Pythagoras theorem ,
H^2 = B^2 + P^2
= 3^2 + 3^2
= 9+9
= 18
H = √18
Now , by Pythagoras theorem ,
H^2 = B^2 + P^2
= 3^2 + 3^2
= 9+9
= 18
H = √18
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the diagonals of a rhombus are of length 12cm and 24cm. find the length of its sides
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