The diagonals of a rhombus are of measurel2 cm and 16 cm. Find the length of the side of the rhombus
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area = 1/2×(product of diagnostic)
1/2×(12×16)
=96cm².
side=96/4=24cm
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Step-by-step explanation:
Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm. We know that the diagonals of rhombus bisect at right angles.
⇒ AO = 16/2 = 8 cm
⇒ BO = 12/2 = 6 cm
In right angled △AOB
By using Pythagoras theorem,
⇒ AB^2 = AO^2+BO^2
⇒ AB^2 = 8^2 + 6^2
⇒ AB^2 = 64+36
⇒ AB^2 = 100
⇒ AB = √100
⇒ AB = 10 cm
∴ Side of a rhombus is 10cm.
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