Math, asked by swatibhamare4, 6 months ago

The diagonals of a rhombus are of measurel2 cm and 16 cm. Find the length of the side of the rhombus​

Answers

Answered by anuragyadav3dx
0

Answer:

area = 1/2×(product of diagnostic)

1/2×(12×16)

=96cm².

side=96/4=24cm

Answered by Anonymous
0

Answer:

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Step-by-step explanation:

Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm. We know that the diagonals of rhombus bisect at right angles.

⇒  AO =  16/2 = 8 cm

⇒  BO = 12/2 = 6 cm

In right angled △AOB

By using Pythagoras theorem,

⇒  AB^2 = AO^2+BO^2

⇒  AB^2 = 8^2 + 6^2

⇒  AB^2 = 64+36

⇒  AB^2 = 100

⇒  AB = √100

⇒  AB = 10 cm

∴  Side of a rhombus is 10cm.

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