the diagonals of a rhombus are12 cm and 16 cm find the leanth of each side
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hey
here is ur answer
hope it helps you
here is ur answer
hope it helps you
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Answered by
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Heya mate,
Here is your answer,
In a Rhombus ABCD
Diagonals intersect at O
AC=12cm
BD=16cm
half of AC=AO
half of 12cm=A0
AO=6cm
half of BD=OD
half of 16cm=OD
OD=8cm
AD=side of rhombus ABCD
side2=AO2 + OD2 (pytha. theorum)
side2=62 + 82
side2=36 + 64
side2=100
side2=102
side=10cm
Hope this helps and you understood it.
if you have any doubt or want help you can ask me. i would like to help.
Thank you
#Sneha
Here is your answer,
In a Rhombus ABCD
Diagonals intersect at O
AC=12cm
BD=16cm
half of AC=AO
half of 12cm=A0
AO=6cm
half of BD=OD
half of 16cm=OD
OD=8cm
AD=side of rhombus ABCD
side2=AO2 + OD2 (pytha. theorum)
side2=62 + 82
side2=36 + 64
side2=100
side2=102
side=10cm
Hope this helps and you understood it.
if you have any doubt or want help you can ask me. i would like to help.
Thank you
#Sneha
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