Math, asked by saumya45, 1 year ago

the diagonals of a rhombus are12 cm and 16 cm find the leanth of each side

Answers

Answered by rohan5101
1
hey
here is ur answer
hope it helps you
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Answered by Sneha3123
1
Heya mate,
Here is your answer,

In a Rhombus ABCD 
Diagonals intersect at O
AC=12cm
​BD=16cm

half of AC=AO
half of 12cm=A0
​AO=6cm

half of BD=OD
half of 16cm=OD
OD=8cm

AD=side of rhombus ABCD
side2=AO​2 + OD2 (pytha. theorum)
side2=62 + 82
side2=36 + 64
side2=100
side2=102
side=10cm



Hope this helps and you understood it.

if you have any doubt or want help you can ask me. i would like to help.

Thank you

#Sneha
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