English, asked by altafkhan7109393, 7 months ago

the diagonals of a Rhombus bisect each other of a measure 8cm and 6cm find its perimeter​

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Answered by 2shrestha28
0

AnThe diagonals perpendicularly bisect each other in rhombus

∴a= root (4)^2 + (3)^2 = 5cm

∴ perimeter = 4 × 5 = 20cm

Explanation:

Answered by dhwani01
1
Ur answer is in the pic below

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