The diagonals of a rhombus intersect at O. If AC=8cm and BD=6cm. Find the length of its sides.
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If diagonal AC=6 cm and BD=8cm and they intersect at a point O, then OC=6/2=3cm and OD =8/2=4 cm. As they intersect at Right angles, by applying Pythogoras theorem we get the side of Rhombus=SQRT(3^2+4^2)=5cm. So, the perimeter=5*4=20 cm.
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