Question

the diagonals of a rhombus measure 10 cm and 24 cm find its perimeter

Answer 1

Here ,

Given :

Diagonal 1 of rhombus = 10 cm

Diagonal 2 of rhombus = 24 cm

To Find :

The perimeter of the rhombus .

Solution :

By using Pythagoras theorem find Out side firstly.

Then using the formula to find perimeter find out the perimeter.

For full solution refer to the above attachment !!

Perimeter =
${ \boxed{ \boxed{ \boxed{ \boxed{ \boxed{ \boxed{52 \: cm}}}}}}}$

★ AhseFurieux ★

Answer 2

Solutions :-

Given :
One Diagonal = d1 = 10 cm
Other Diagonal = d2 = 24 cm

Find the length of side (a) of Rhombus :-

$a = \frac {\sqrt {d1^2 + d2^2}}{2} =\frac {\sqrt {10^2 + 24^2}}{2} = 13 cm$

Now,
Find the perimeter of Rhombus :-

Perimeter of Rhombus = 4 × a
= (4 × 13) cm
= 52 cm

Hence,
Perimeter of Rhombus = 52 cm