Question

The diagonals of a rhombus measure 10cm and 24cm . Find its perimeter

Answer 1

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Answer 2

Hi learner,

Here is your answer,

Perimeter of rhombus when two diagonals are given = 2$\sqrt{ x^{2} + y^{2}}$

So now , the diagonals are x = 10 cm and y = 24 cm.

Substituting the values in the formula ,

Perimeter = 2 $\sqrt{10^{2}+24^{2} }$

                 = 2 $\sqrt{100+576}$

                 = 2$\sqrt{676}$

                 = 2 x 26

                 =52 cm

the perimeter of the rhombus is 52cm.

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