Question

the diagonals of a rhombus measure 12 CM and 16 CM Find its perimeter

Answer 1

Hey !!!

Diagonal of rhombus = 12cm and 16cm

half of diagonal = 6cm and 8cm

by using Pythagoras theorem

at the point o where diangonals are meet at that point there are angle formed 90°
so,

a (side) of rhombus = √p² + b²

a = √6² + 8² = √36+64 =√ 100 = 10cm

now , as we know that Perimeter of rhombus

= 4a = 4×10 = 40cm Ans

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Hope it helps you !!!

@Rajukumar111

Answer 2

Given:

• Diagonals of a rhombus = 12 cm and 16 cm.

To Find:

• Find its Perimeter.

Solution:

• To find the perimeter of the rhombus we should find the length of its side as perimeter = 4a, where a is the length of one side of the rhombus.
• As diagonals of the rhombus are perpendicular, they bisect each other.
• So, 12 cm is considered as 6 cm = x and 16 cm is considered as 8 cm = y
• Side of the rhombus, a = $\sqrt{x^2+y^2} = \sqrt{6^2+8^2} = \sqrt{36+64} = \sqrt{100}$
• a = 10 cm
• Perimeter, p = 4a = 4*10 = 40 cm

The perimeter of rhombus = 40 cm.