Question

the diagonals of a rhombus measure 16 cm and 30 cm. find its perimeters

Answer 1

The diagonals of a Rhombus is 16 cm and 30 cm.
so the half of each diagonals will be respectively 8cm and 15 cm
the diagonals intersect as 90°
so the sides will be---
$\sqrt{ {15}^{2} + {8}^{2} } \: cm \\ = \sqrt{225 + 64} \: cm \\ = \sqrt{289} \: cm \\ = 17 \: cm$
so the sides are 17 cm
so the perimeter of the cube is =(4×17)cm = 68cm
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