Question

The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter. ​

Answer 1

Answer:

Perimeter= 68cm

Step-by-step explanation:

P=4a

a=√(p^2+q^2)

2

Solving forP

P=2p2+q2=2·√[16^2+30^2]=68cm

Answer 2

Given :

⬤ Diagonal of Rhombus measures 26 cm and 30 cm .

To Find :

⬤ Perimeter of Rhombus .

Solution :

OD = BD/2

= 30/2

= 15

OC = AC/2

= 16/2

= 8

Now :

By Using Pythagoras Property :

In ∆ DOC : -

(DC)² = (OD)² + (OC)²

(DC)² = (15)² + (8)²

(DC)² = 225 + 64

(DC)² = 289

DC = √289

DC = 17

Therefore , The Value of DC is 17 .

Formula Used :

$\sf[\:{Perimeter\:of\:Rhombus=4\times{Side}\:]}$

Now :

According to the Formula :

4 × Side

4 × 17

68

Therefore , The Perimeter of Rhombus is 68 cm .